What are the solutions to the equation quadraticformula x^2-6x+13=0 ?

The solutions to the equation quadraticformula x^2-6x+13=0 are x=3+2i,x=3-2i

Find the zeros of quadraticformula x^2-6x+13=0

The zeros of quadraticformula x^2-6x+13=0 are x=3+2i,x=3-2i

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x^{2} - 6 x + 13 = 0

x = 3 + 2 i, x = 3 - 2 i

Solution steps

x^{2} - 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

x = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

x = 3 + 2 i, x = 3 - 2 i

224

2 (15)

b, - 67 b + 6 \leq 9 b + 43

m, m = - (4 + m) + 2

7.4%

What are the solutions to the equation quadraticformula x^2-6x+13=0 ?
The solutions to the equation quadraticformula x^2-6x+13=0 are x=3+2i,x=3-2i
Find the zeros of quadraticformula x^2-6x+13=0
The zeros of quadraticformula x^2-6x+13=0 are x=3+2i,x=3-2i