What are the solutions to the equation quadraticformula 4x^2-64=0 ?

The solutions to the equation quadraticformula 4x^2-64=0 are x=4,x=-4

Find the zeros of quadraticformula 4x^2-64=0

The zeros of quadraticformula 4x^2-64=0 are x=4,x=-4

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4 x^{2} - 64 = 0

x = 4, x = - 4

Solution steps

4 x^{2} - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 64 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 64) = 32

x_{1, 2} = \frac{- 0 \pm 32}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 0 + 32}{2 \cdot 4}, x_{2} = \frac{- 0 - 32}{2 \cdot 4}

x = \frac{- 0 + 32}{2 \cdot 4} : 4

x = \frac{- 0 - 32}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = 4, x = - 4

x, 6 x = 12

\frac{( 4 a )}{( 4 a b ^{2} )} - \frac{( 2 a - 3 b )}{4}

7 \frac{1}{2} %

\frac{21}{75}

(0.25)^{3}

What are the solutions to the equation quadraticformula 4x^2-64=0 ?
The solutions to the equation quadraticformula 4x^2-64=0 are x=4,x=-4
Find the zeros of quadraticformula 4x^2-64=0
The zeros of quadraticformula 4x^2-64=0 are x=4,x=-4