What are the solutions to the equation quadraticformula 2x^2=7x-3 ?

The solutions to the equation quadraticformula 2x^2=7x-3 are x=3,x= 1/2

Find the zeros of quadraticformula 2x^2=7x-3

The zeros of quadraticformula 2x^2=7x-3 are x=3,x= 1/2

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2 x^{2} = 7 x - 3

x = 3, x = \frac{1}{2}

Decimal

x = 3, x = 0.5

Solution steps

2 x^{2} = 7 x - 3

Move

3

to the left side

2 x^{2} + 3 = 7 x

Move

7 x

to the left side

2 x^{2} + 3 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 \cdot 3 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 2}

x = \frac{- ( - 7 ) + 5}{2 \cdot 2} : 3

x = \frac{- ( - 7 ) - 5}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{2}

What are the solutions to the equation quadraticformula 2x^2=7x-3 ?
The solutions to the equation quadraticformula 2x^2=7x-3 are x=3,x= 1/2
Find the zeros of quadraticformula 2x^2=7x-3
The zeros of quadraticformula 2x^2=7x-3 are x=3,x= 1/2