What are the solutions to the equation x^2-3x+9/4 =0 ?

The solutions to the equation x^2-3x+9/4 =0 are x= 3/2

Find the zeros of x^2-3x+9/4 =0

The zeros of x^2-3x+9/4 =0 are x= 3/2

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x^{2} - 3 x + \frac{9}{4} = 0

x = \frac{3}{2}

Solution steps

x^{2} - 3 x + \frac{9}{4} = 0

Multiply both sides by

4

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

8 c^{4} + 10 c^{2} - 3

2 x > - 4

2 x^{2} + 20 x + 6 = 0

u + 50 = 4

7 k^{2} - 6 k + 3 = 3

What are the solutions to the equation x^2-3x+9/4 =0 ?
The solutions to the equation x^2-3x+9/4 =0 are x= 3/2
Find the zeros of x^2-3x+9/4 =0
The zeros of x^2-3x+9/4 =0 are x= 3/2