log_{8}(x)=x+1

解答

lo g_{8} (x) = x + 1

x \in R 无解

求解步骤

lo g_{8} (x) = x + 1

若

f (x) = g (x)

，则

a^{f (x)} = a^{g (x)}

8^{l o g_{8} (x)} = 8^{x + 1}

化简

8^{l o g_{8} (x)} : x

x = 8^{x + 1}

解

x = 8^{x + 1} : x \in R

无解

x \in R 无解

lo g_{x} (0.25) = - 2

6 - lo g_{10} (8 x + 4) = 4

2 ln (x) + ln (2) = ln (x + 3)

lo g_{2} (5 y^{2} + 2 y - 8) = 4

lo g_{10} (4) + lo g_{10} (5 x) = 2