What are the solutions to the equation 2x^2-5=-55 ?

The solutions to the equation 2x^2-5=-55 are x=5i,x=-5i

Find the zeros of 2x^2-5=-55

The zeros of 2x^2-5=-55 are x=5i,x=-5i

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2 x^{2} - 5 = - 55

x = 5 i, x = - 5 i

Solution steps

2 x^{2} - 5 = - 55

Move

5

to the right side

2 x^{2} = - 50

Divide both sides by

2

x^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 25, x = - - 25

- 25 = 5 i

- - 25 = - 5 i

x = 5 i, x = - 5 i

3 x^{2} + 3 x - 36

\frac{k}{4} - 2 = 1

\frac{1}{2} x + 7 - \frac{1}{4} x = \frac{19}{2}

x^{2} - 3 x + 2 \leq 0

(3 x - 7) (2 x + 5) = 0

What are the solutions to the equation 2x^2-5=-55 ?
The solutions to the equation 2x^2-5=-55 are x=5i,x=-5i
Find the zeros of 2x^2-5=-55
The zeros of 2x^2-5=-55 are x=5i,x=-5i