What are the solutions to the equation (r+4)^2=13 ?

The solutions to the equation (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4

Find the zeros of (r+4)^2=13

The zeros of (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(r + 4)^{2} = 13

r = 13 - 4, r = - 13 - 4

Solution steps

(r + 4)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r + 4 = 13 : r = 13 - 4

Solve

r + 4 = - 13 : r = - 13 - 4

The solutions to the quadratic equation are:

r = 13 - 4, r = - 13 - 4

g^{4} + 24 g^{3} + 12 g^{2} + 4 g

(\frac{\frac{6}{5}}{\frac{3}{5}})^{5}

\frac{12}{6}

- 2 + - 18

4 (2 y - 1) - 2 (2 y) = 2

What are the solutions to the equation (r+4)^2=13 ?
The solutions to the equation (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4
Find the zeros of (r+4)^2=13
The zeros of (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4