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受欢迎的代数 >

x^3=1-i

解答

x^{3} = 1 - i

解答

x = \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 - 3 )}{4}, x = - \frac{2 ^{\frac{2}{3}} ( - 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4}, x = - \frac{2 ^{\frac{2}{3}}}{2} - i \frac{2 ^{\frac{2}{3}}}{2}

求解步骤

x^{3} = 1 - i

For

z^{n} = a

the solutions are

z_{k} = n ∣ a ∣ (cos (\frac{ar g ( a ) + 2 kπ}{n}) + i sin (\frac{ar g ( a ) + 2 kπ}{n})),

k = 0, 1, \dots, n - 1

对于

n = 3, a = 1 - i

∣ a ∣ = 2

ar g (a) = - \frac{π}{4}

x = 32 (cos (\frac{- \frac{π}{4} + 2 \cdot 0 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 0 π}{3})), x = 32 (cos (\frac{- \frac{π}{4} + 2 \cdot 1 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 1 π}{3})), x = 32 (cos (\frac{- \frac{π}{4} + 2 \cdot 2 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 2 π}{3}))

化简

32 (cos (\frac{- \frac{π}{4} + 2 \cdot 0 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 0 π}{3})) : \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 - 3 )}{4}

化简

32 (cos (\frac{- \frac{π}{4} + 2 \cdot 1 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 1 π}{3})) : - \frac{2 ^{\frac{2}{3}} ( - 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4}

化简

32 (cos (\frac{- \frac{π}{4} + 2 \cdot 2 π}{3}) + i sin (\frac{- \frac{π}{4} + 2 \cdot 2 π}{3})) : - \frac{2 ^{\frac{2}{3}}}{2} - i \frac{2 ^{\frac{2}{3}}}{2}

x = \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 - 3 )}{4}, x = - \frac{2 ^{\frac{2}{3}} ( - 1 + 3 )}{4} + i \frac{2 ^{\frac{2}{3}} ( 1 + 3 )}{4}, x = - \frac{2 ^{\frac{2}{3}}}{2} - i \frac{2 ^{\frac{2}{3}}}{2}

流行的例子

2 x^{4} - 48 x^{2} = 0

x^{2} - x^{3} = 12

8 x^{3} - 98 x = 0

9 x^{5} = 27 x^{3}

4 x^{3} - 9 x^{2} - 1 = 0