What is the answer to solvefor x,e^{x/2}=4lnx ?

The answer to solvefor x,e^{x/2}=4lnx is x\approx 1.92309,2.89429

solvefor x,e^{x/2}=4lnx

solve for

x, e^{\frac{x}{2}} = 4 ln (x)

x \approx 1.92309, 2.89429

Solution steps

e^{\frac{x}{2}} = 4 ln (x)

Find the difference function

f (x) = e^{\frac{x}{2}} - 4 ln (x)

Look for the function's extreme points

Extreme Points of

e^{\frac{x}{2}} - 4 ln (x), x > 0 :

Minimum

(2.40433 \dots, - 0.18177 \dots)

Check function behavior at domain edges:

0, \infty

x \to 0 + lim (e^{\frac{x}{2}} - 4 ln (x)) = \infty

x \to \infty lim (e^{\frac{x}{2}} - 4 ln (x)) = \infty

The interval between every consecutive point pair is monotone

x f (x) 0 \infty 2.40433 \dots - 0.18177 \dots \infty \infty

Check every interval, if the signs at the edges are different, find the X intersection using Brent method

Between

(0, \infty)

and

(2.40433 \dots, - 0.18177 \dots)

1.92309

Between

(2.40433 \dots, - 0.18177 \dots)

and

(\infty, \infty)

2.89429

x \approx 1.92309, 2.89429

What is the answer to solvefor x,e^{x/2}=4lnx ?
The answer to solvefor x,e^{x/2}=4lnx is x\approx 1.92309,2.89429