What are the solutions to the equation x^2+x=-9-16 ?

The solutions to the equation x^2+x=-9-16 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2

Find the zeros of x^2+x=-9-16

The zeros of x^2+x=-9-16 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2

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x^{2} + x = - 9 - 16

x = - \frac{1}{2} + i \frac{3 11}{2}, x = - \frac{1}{2} - i \frac{3 11}{2}

Solution steps

x^{2} + x = - 9 - 16

Refine

x^{2} + x = - 25

Move

25

to the left side

x^{2} + x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 25 : 311 i

x_{1, 2} = \frac{- 1 \pm 3 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 11 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 11 i}{2 \cdot 1}

x = \frac{- 1 + 3 11 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3 11}{2}

x = \frac{- 1 - 3 11 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3 11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3 11}{2}, x = - \frac{1}{2} - i \frac{3 11}{2}

x + 9 = 3 - 5 x

2 b^{2} - 5 b + 7 = 0

- 3 v - 14.47 > - 5.47

50 v^{2} + 40 v d + 8 d^{2}

4 x^{2} - x

What are the solutions to the equation x^2+x=-9-16 ?
The solutions to the equation x^2+x=-9-16 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2
Find the zeros of x^2+x=-9-16
The zeros of x^2+x=-9-16 are x=-1/2+i(3sqrt(11))/2 ,x=-1/2-i(3sqrt(11))/2