What are the solutions to the equation 9x^2+9x-4=0 ?

The solutions to the equation 9x^2+9x-4=0 are x= 1/3 ,x=-4/3

Find the zeros of 9x^2+9x-4=0

The zeros of 9x^2+9x-4=0 are x= 1/3 ,x=-4/3

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9 x^{2} + 9 x - 4 = 0

x = \frac{1}{3}, x = - \frac{4}{3}

Solution steps

9 x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

9^{2} - 4 \cdot 9 (- 4) = 15

x_{1, 2} = \frac{- 9 \pm 15}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 9 + 15}{2 \cdot 9}, x_{2} = \frac{- 9 - 15}{2 \cdot 9}

x = \frac{- 9 + 15}{2 \cdot 9} : \frac{1}{3}

x = \frac{- 9 - 15}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{4}{3}

120 = 16 t^{2}

\frac{2 ^{- 1}}{- 1}

2^{8} - 1

- a + 2 = 1

2 x^{2} - 5 x + 1 = 4

What are the solutions to the equation 9x^2+9x-4=0 ?
The solutions to the equation 9x^2+9x-4=0 are x= 1/3 ,x=-4/3
Find the zeros of 9x^2+9x-4=0
The zeros of 9x^2+9x-4=0 are x= 1/3 ,x=-4/3