q^2-350q+25000=0

解

q^{2} - 350 q + 25000 = 0

q = 250, q = 100

解答ステップ

q^{2} - 350 q + 25000 = 0

解くとthe二次式

q_{1, 2} = \frac{- ( - 350 ) \pm ( - 350 ) ^{2} - 4 \cdot 1 \cdot 25000}{2 \cdot 1}

(- 350)^{2} - 4 \cdot 1 \cdot 25000 = 150

q_{1, 2} = \frac{- ( - 350 ) \pm 150}{2 \cdot 1}

解を分離する

q_{1} = \frac{- ( - 350 ) + 150}{2 \cdot 1}, q_{2} = \frac{- ( - 350 ) - 150}{2 \cdot 1}

q = \frac{- ( - 350 ) + 150}{2 \cdot 1} : 250

q = \frac{- ( - 350 ) - 150}{2 \cdot 1} : 100

二次equationの解:

q = 250, q = 100