solvefor y,yx^2+2y=5x

解答

求解

y, y x^{2} + 2 y = 5 x

y = \frac{5 x}{x ^{2} + 2}; x \neq = 2 i, x \neq = - 2 i

求解步骤

y x^{2} + 2 y = 5 x

分解

y x^{2} + 2 y : y (x^{2} + 2)

y (x^{2} + 2) = 5 x

两边除以

x^{2} + 2; x \neq = 2 i, x \neq = - 2 i

y = \frac{5 x}{x ^{2} + 2}; x \neq = 2 i, x \neq = - 2 i

so l v e f or y, y^{2} = x^{2} + 6 x + 9

9 p^{2} + 17 p + 12 = 3 p^{2}

4 x^{2} - 5 x = - 1

so l v e f or k, 6 x^{2} + k x + 6 = 0

8^{2} = 8 x^{2}