What are the solutions to the equation x^2-4x-20=0 ?

The solutions to the equation x^2-4x-20=0 are x=2(1+sqrt(6)),x=2(1-sqrt(6))

Find the zeros of x^2-4x-20=0

The zeros of x^2-4x-20=0 are x=2(1+sqrt(6)),x=2(1-sqrt(6))

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x^{2} - 4 x - 20 = 0

x = 2 (1 + 6), x = 2 (1 - 6)

Solution steps

x^{2} - 4 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 20) = 46

x_{1, 2} = \frac{- ( - 4 ) \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 6}{2 \cdot 1} : 2 (1 + 6)

x = \frac{- ( - 4 ) - 4 6}{2 \cdot 1} : 2 (1 - 6)

The solutions to the quadratic equation are:

x = 2 (1 + 6), x = 2 (1 - 6)

r^{2} + r = 0

6 k^{2} - 42 k + 72 = 0

36 x^{2} - 121

r^{2} - 10 r + 25 = 1

(6 x - 7) = (4 x + 23)

What are the solutions to the equation x^2-4x-20=0 ?
The solutions to the equation x^2-4x-20=0 are x=2(1+sqrt(6)),x=2(1-sqrt(6))
Find the zeros of x^2-4x-20=0
The zeros of x^2-4x-20=0 are x=2(1+sqrt(6)),x=2(1-sqrt(6))