What are the solutions to the equation 0=x^2-8x+20 ?

The solutions to the equation 0=x^2-8x+20 are x=4+2i,x=4-2i

Find the zeros of 0=x^2-8x+20

The zeros of 0=x^2-8x+20 are x=4+2i,x=4-2i

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0 = x^{2} - 8 x + 20

x = 4 + 2 i, x = 4 - 2 i

Solution steps

0 = x^{2} - 8 x + 20

Switch sides

x^{2} - 8 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 20 : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 i}{2 \cdot 1} : 4 + 2 i

x = \frac{- ( - 8 ) - 4 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

x = 4 + 2 i, x = 4 - 2 i

4 x^{2} - 13 x y + 10 y^{2}

x^{2} + 6 x + 36 = 0

\frac{2 x - 3}{2} = \frac{4 x}{7}

\frac{( - 6 ) ^{8}}{( - 6 ) ^{5}}

What are the solutions to the equation 0=x^2-8x+20 ?
The solutions to the equation 0=x^2-8x+20 are x=4+2i,x=4-2i
Find the zeros of 0=x^2-8x+20
The zeros of 0=x^2-8x+20 are x=4+2i,x=4-2i