What is ((8+i))/((2-3i)) ?

The solution to ((8+i))/((2-3i)) is 1+2i

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simplify ((8+i))/((2-3i))

simplify

\frac{( 8 + i )}{( 2 - 3 i )}

1 + 2 i

Solution steps

\frac{8 + i}{2 - 3 i}

Multiply by the conjugate

\frac{2 + 3 i}{2 + 3 i}

= \frac{( 8 + i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )}

Simplify

\frac{( 8 + i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )} : \frac{13 + 26 i}{13}

= \frac{13 + 26 i}{13}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{13}{13} + \frac{26}{13} i

Simplify

\frac{13}{13} + \frac{26}{13} i : 1 + 2 i

= 1 + 2 i

5 ∣ x - 3 ∣ < 0.004

\frac{ln ( 2 )}{0.02}

(2 - \frac{5}{2})^{2}

6 x^{2} - 13 x - 63

a^{- 7}