What are the solutions to the equation x^2-9x+22=0 ?

The solutions to the equation x^2-9x+22=0 are x= 9/2+i(sqrt(7))/2 ,x= 9/2-i(sqrt(7))/2

Find the zeros of x^2-9x+22=0

The zeros of x^2-9x+22=0 are x= 9/2+i(sqrt(7))/2 ,x= 9/2-i(sqrt(7))/2

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x^{2} - 9 x + 22 = 0

x = \frac{9}{2} + i \frac{7}{2}, x = \frac{9}{2} - i \frac{7}{2}

Solution steps

x^{2} - 9 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot 22 : 7 i

x_{1, 2} = \frac{- ( - 9 ) \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 7 i}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 7 i}{2 \cdot 1}

x = \frac{- ( - 9 ) + 7 i}{2 \cdot 1} : \frac{9}{2} + i \frac{7}{2}

x = \frac{- ( - 9 ) - 7 i}{2 \cdot 1} : \frac{9}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2} + i \frac{7}{2}, x = \frac{9}{2} - i \frac{7}{2}

- \frac{1}{2} - \frac{3}{2}

(1 + 73) (1 - 73)

x^{2} - 4 x - 21 < 0

e^{x}

\frac{2}{3} (9)

What are the solutions to the equation x^2-9x+22=0 ?
The solutions to the equation x^2-9x+22=0 are x= 9/2+i(sqrt(7))/2 ,x= 9/2-i(sqrt(7))/2
Find the zeros of x^2-9x+22=0
The zeros of x^2-9x+22=0 are x= 9/2+i(sqrt(7))/2 ,x= 9/2-i(sqrt(7))/2