What are the solutions to the equation x^2+4x=0 ?

The solutions to the equation x^2+4x=0 are x=0,x=-4

Find the zeros of x^2+4x=0

The zeros of x^2+4x=0 are x=0,x=-4

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x^{2} + 4 x = 0

x = 0, x = - 4

Solution steps

x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 \cdot 1}, x_{2} = \frac{- 4 - 4}{2 \cdot 1}

x = \frac{- 4 + 4}{2 \cdot 1} : 0

x = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

T + (\frac{3 T}{2}) + (\frac{( T + 2 )}{2 T}) = 4 T^{2}

(\frac{x ^{2}}{5})^{3}

x^{2} - 3 x y - 18 y^{2}

13 a - 13 b + 39

3^{2} = x + 5

What are the solutions to the equation x^2+4x=0 ?
The solutions to the equation x^2+4x=0 are x=0,x=-4
Find the zeros of x^2+4x=0
The zeros of x^2+4x=0 are x=0,x=-4