What are the solutions to the equation 3p^2-36=3p ?

The solutions to the equation 3p^2-36=3p are p=4,p=-3

Find the zeros of 3p^2-36=3p

The zeros of 3p^2-36=3p are p=4,p=-3

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3 p^{2} - 36 = 3 p

p = 4, p = - 3

Solution steps

3 p^{2} - 36 = 3 p

Move

3 p

to the left side

3 p^{2} - 36 - 3 p = 0

Write in the standard form

a x^{2} + b x + c = 0

3 p^{2} - 3 p - 36 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 36) = 21

p_{1, 2} = \frac{- ( - 3 ) \pm 21}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- ( - 3 ) + 21}{2 \cdot 3}, p_{2} = \frac{- ( - 3 ) - 21}{2 \cdot 3}

p = \frac{- ( - 3 ) + 21}{2 \cdot 3} : 4

p = \frac{- ( - 3 ) - 21}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

p = 4, p = - 3

1 x^{2} - 11 x + 15 = 0

416

36 x^{2} - 96 x + 64

\frac{x - 8}{5} = \frac{x + 4}{9}

2 < \frac{1}{3} - 2 x < 5

What are the solutions to the equation 3p^2-36=3p ?
The solutions to the equation 3p^2-36=3p are p=4,p=-3
Find the zeros of 3p^2-36=3p
The zeros of 3p^2-36=3p are p=4,p=-3