12i+12yi^2=-24xi+6

解答

12 i + 12 y i^{2} = - 24 x i + 6

x = - \frac{1}{2}, y = - \frac{1}{2}

求解步骤

12 i + 12 y i^{2} = - 24 x i + 6

化简

12 i + 12 y i^{2} : 12 i - 12 y

12 i - 12 y = - 24 x i + 6

复数仅在实部和虚部均相等时才相等改写为方程组:

[- 12 y = 6 12 = - 24 x]

[- 12 y = 6 12 = - 24 x] : x = - \frac{1}{2}, y = - \frac{1}{2}

x = - \frac{1}{2}, y = - \frac{1}{2}

a - bi = (a + bi) i

3 x + (y - 2) i = (5 - 2 x) + (3 y - 8) i

+ 28 + 2 i + z^{2} = 30 - 2 i, z^{1} = 3

(5 x - 2 y) + (8 x + 10 y) i = 38 + 8 i

- (b + 2) i - 8 + a = b - 2 + (3 b - 6) i