0=ln(2x+3)

Lösung

0 = ln (2 x + 3)

x = - 1

Schritte zur Lösung

0 = ln (2 x + 3)

Wende die log Regel an

1 = 2 x + 3

Löse

1 = 2 x + 3 : x = - 1

x = - 1

lo g_{5} (- 3 x + 8) = 1

x = e^{l n (x)}

- 2 + 2 ln (3 x) = 17

2 lo g_{10} (x) = lo g_{10} (25)

d b = 10 lo g_{10} (x)