What are the solutions to the equation 89x^2+38x-45=0 ?

The solutions to the equation 89x^2+38x-45=0 are x=(-19+sqrt(4366))/(89),x=-(19+sqrt(4366))/(89)

Find the zeros of 89x^2+38x-45=0

The zeros of 89x^2+38x-45=0 are x=(-19+sqrt(4366))/(89),x=-(19+sqrt(4366))/(89)

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89 x^{2} + 38 x - 45 = 0

x = \frac{- 19 + 4366}{89}, x = - \frac{19 + 4366}{89}

Solution steps

89 x^{2} + 38 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 38 \pm 3 8 ^{2} - 4 \cdot 89 ( - 45 )}{2 \cdot 89}

3 8^{2} - 4 \cdot 89 (- 45) = 24366

x_{1, 2} = \frac{- 38 \pm 2 4366}{2 \cdot 89}

Separate the solutions

x_{1} = \frac{- 38 + 2 4366}{2 \cdot 89}, x_{2} = \frac{- 38 - 2 4366}{2 \cdot 89}

x = \frac{- 38 + 2 4366}{2 \cdot 89} : \frac{- 19 + 4366}{89}

x = \frac{- 38 - 2 4366}{2 \cdot 89} : - \frac{19 + 4366}{89}

The solutions to the quadratic equation are:

x = \frac{- 19 + 4366}{89}, x = - \frac{19 + 4366}{89}

1 + 2

7 x - 7 = 2 x - 1

5 (2 + x) - x = 10 + 4 (x + 1)

2 n^{2} + 5 n + 3 = 0

lo g_{5} (\frac{1}{1000})

What are the solutions to the equation 89x^2+38x-45=0 ?
The solutions to the equation 89x^2+38x-45=0 are x=(-19+sqrt(4366))/(89),x=-(19+sqrt(4366))/(89)
Find the zeros of 89x^2+38x-45=0
The zeros of 89x^2+38x-45=0 are x=(-19+sqrt(4366))/(89),x=-(19+sqrt(4366))/(89)