What is the answer to (x+1)/2+(5+x)/6 =1+(9-2x)/3 ?

The answer to (x+1)/2+(5+x)/6 =1+(9-2x)/3 is x=2

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(x+1)/2+(5+x)/6 =1+(9-2x)/3

\frac{x + 1}{2} + \frac{5 + x}{6} = 1 + \frac{9 - 2 x}{3}

x = 2

Solution steps

\frac{x + 1}{2} + \frac{5 + x}{6} = 1 + \frac{9 - 2 x}{3}

Multiply by LCM

3 (x + 1) + 5 + x = 6 + 2 (- 2 x + 9)

Expand

3 (x + 1) + 5 + x : 4 x + 8

Expand

6 + 2 (- 2 x + 9) : - 4 x + 24

4 x + 8 = - 4 x + 24

Move

8

to the right side

4 x = - 4 x + 16

Move

4 x

to the left side

8 x = 16

Divide both sides by

8

x = 2

\frac{3 x}{5} + \frac{x}{9} = - 1

5 (z + 6) \leq 40

\frac{1}{3} + \frac{1}{2} (- \frac{2}{5})

14 b^{2} - 2 + 3 b

4 \cdot 2^{- 2}

What is the answer to (x+1)/2+(5+x)/6 =1+(9-2x)/3 ?
The answer to (x+1)/2+(5+x)/6 =1+(9-2x)/3 is x=2
Solve for x: (x+1)/2+(5+x)/6 =1+(9-2x)/3
The solution is x=2