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Beliebt Algebra >

vereinfachen (x^{1/2}y^{1/4}z^{1/2})^8

Lösung

vereinfachen

(x^{\frac{1}{2}} y^{\frac{1}{4}} z^{\frac{1}{2}})^{8}

Lösung

x^{4} y^{2} z^{4}

Schritte zur Lösung

(x^{\frac{1}{2}} y^{\frac{1}{4}} z^{\frac{1}{2}})^{8}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(x^{\frac{1}{2}} y^{\frac{1}{4}} z^{\frac{1}{2}})^{8} = (x^{\frac{1}{2}})^{8} (y^{\frac{1}{4}})^{8} (z^{\frac{1}{2}})^{8}

= (x^{\frac{1}{2}})^{8} (y^{\frac{1}{4}})^{8} (z^{\frac{1}{2}})^{8}

Vereinfache

(x^{\frac{1}{2}})^{8} : x^{4}

= x^{4} (y^{\frac{1}{4}})^{8} (z^{\frac{1}{2}})^{8}

Vereinfache

(y^{\frac{1}{4}})^{8} : y^{2}

= x^{4} y^{2} (z^{\frac{1}{2}})^{8}

Vereinfache

(z^{\frac{1}{2}})^{8} : z^{4}

= x^{4} y^{2} z^{4}

Beliebte Beispiele

\frac{1}{4} (- 2)^{2}

8 = \frac{3}{2} (9 x - 6)

solvefor t,1-(1+r)^2-t=((p*r))/m

so l v e f or t, 1 - (1 + r)^{2} - t = \frac{( p \cdot r )}{m}

x^2-5x-56=-2x-2

x^{2} - 5 x - 56 = - 2 x - 2

faktorisieren 3x^3+15x^2+18x

f a c t or 3 x^{3} + 15 x^{2} + 18 x