ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

solvefor x,f=5x^3+1f(-8)

解

解く

x, f = 5 x^{3} + 1 f (- 8)

解

x = 3 \frac{f - f ( - 8 )}{5}, x = - \frac{3 \frac{f - f ( - 8 )}{5}}{2} + \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i, x = - \frac{3 \frac{f - f ( - 8 )}{5}}{2} - \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i

解答ステップ

f = 5 x^{3} + 1 \cdot f (- 8)

辺を交換する

5 x^{3} + 1 \cdot f (- 8) = f

1 f (- 8)

を右側に移動します

5 x^{3} = f - f (- 8)

以下で両辺を割る

5

x^{3} = \frac{f - f ( - 8 )}{5}

x^{3} = f (a)

では, 解は

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 \frac{f - f ( - 8 )}{5}, x = 3 \frac{f - f ( - 8 )}{5} \frac{- 1 + 3 i}{2}, x = 3 \frac{f - f ( - 8 )}{5} \frac{- 1 - 3 i}{2}

簡素化

3 \frac{f - f ( - 8 )}{5} \frac{- 1 + 3 i}{2} : - \frac{3 \frac{f - f ( - 8 )}{5}}{2} + \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i

簡素化

3 \frac{f - f ( - 8 )}{5} \frac{- 1 - 3 i}{2} : - \frac{3 \frac{f - f ( - 8 )}{5}}{2} - \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i

x = 3 \frac{f - f ( - 8 )}{5}, x = - \frac{3 \frac{f - f ( - 8 )}{5}}{2} + \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i, x = - \frac{3 \frac{f - f ( - 8 )}{5}}{2} - \frac{3 \frac{f - f ( - 8 )}{5} 3}{2} i

グラフ

人気の例

-12=5(6x^4)7(x^6)

- 12 = 5 (6 x^{4}) 7 (x^{6})

(x + 1)^{3} - 27 = 0

x^{3} + x^{2} = 6 x

(5x-2)^3-(5x-2)=0

(5 x - 2)^{3} - (5 x - 2) = 0

(x + 1)^{3} + x + 1 = 0