What are the solutions to the equation 6x^2+40x+50=0 ?

The solutions to the equation 6x^2+40x+50=0 are x=-5/3 ,x=-5

Find the zeros of 6x^2+40x+50=0

The zeros of 6x^2+40x+50=0 are x=-5/3 ,x=-5

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6 x^{2} + 40 x + 50 = 0

x = - \frac{5}{3}, x = - 5

Solution steps

6 x^{2} + 40 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 6 \cdot 50}{2 \cdot 6}

4 0^{2} - 4 \cdot 6 \cdot 50 = 20

x_{1, 2} = \frac{- 40 \pm 20}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 40 + 20}{2 \cdot 6}, x_{2} = \frac{- 40 - 20}{2 \cdot 6}

x = \frac{- 40 + 20}{2 \cdot 6} : - \frac{5}{3}

x = \frac{- 40 - 20}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - 5

7 x^{4} + 51 x^{2} + 14

- 4 (x + 2) = - 40

2 x - 1 = 1

8 x^{2} + 14 x = 15

(a^{\frac{1}{2}})^{3}

What are the solutions to the equation 6x^2+40x+50=0 ?
The solutions to the equation 6x^2+40x+50=0 are x=-5/3 ,x=-5
Find the zeros of 6x^2+40x+50=0
The zeros of 6x^2+40x+50=0 are x=-5/3 ,x=-5