What are the solutions to the equation x^2-8x=-16 ?

The solutions to the equation x^2-8x=-16 are x=4

Find the zeros of x^2-8x=-16

The zeros of x^2-8x=-16 are x=4

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x^{2} - 8 x = - 16

x = 4

Solution steps

x^{2} - 8 x = - 16

Move

16

to the left side

x^{2} - 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 8 )}{2 \cdot 1}

\frac{- ( - 8 )}{2 \cdot 1} = 4

x = 4

The solution to the quadratic equation is:

x = 4

(p - q) (p - q)

(\infty - 3) \infty < 4 (\infty + 2)

54 g + 71 \leq - 37

- 250

2 x^{2} + 5 = 41

What are the solutions to the equation x^2-8x=-16 ?
The solutions to the equation x^2-8x=-16 are x=4
Find the zeros of x^2-8x=-16
The zeros of x^2-8x=-16 are x=4