2^{x+1}=5^x

Lösung

2^{x + 1} = 5^{x}

x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

Dezimale

x = 0.75647 \dots

Schritte zur Lösung

2^{x + 1} = 5^{x}

Wende Exponentenregel an

(x + 1) ln (2) = x ln (5)

Löse

(x + 1) ln (2) = x ln (5) : x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

3^{x} - 3^{x - 2} = A \cdot 3^{x}

4^{2 x + 1} = 1

5^{4 x + 2} = 37500

8 \cdot 5^{- \frac{t}{9}} = 346

x^{2} e^{x} = 0