2^{-x}=5

Lösung

2^{- x} = 5

x = - \frac{ln ( 5 )}{ln ( 2 )}

Dezimale

x = - 2.32192 \dots

Schritte zur Lösung

2^{- x} = 5

Wende Exponentenregel an

- x ln (2) = ln (5)

Löse

- x ln (2) = ln (5) : x = - \frac{ln ( 5 )}{ln ( 2 )}

x = - \frac{ln ( 5 )}{ln ( 2 )}

(e^{4})^{x} (e^{x})^{2} = e^{1} 2

5^{2 x - 1} = 5

3^{x - 2} = 9

6 4^{x} = 16

2 7^{5 x - 6} = 9^{7 x + 3}