3^xe^{4x-1}=5

Lösung

3^{x} e^{4 x - 1} = 5

x = \frac{ln ( 5 ) + 1}{ln ( 3 ) + 4}

Dezimale

x = 0.51179 \dots

Schritte zur Lösung

3^{x} e^{4 x - 1} = 5

Wende Exponentenregel an

(x + lo g_{3} (e) (4 x - 1)) ln (3) = ln (5)

Löse

(x + lo g_{3} (e) (4 x - 1)) ln (3) = ln (5) : x = \frac{ln ( 5 ) + 1}{ln ( 3 ) + 4}

x = \frac{ln ( 5 ) + 1}{ln ( 3 ) + 4}

9 = e^{2 x - 2}

2^{x + 5} \cdot 8 = 1 6^{2 x + 2}

8^{x} = 1

e^{3 x} - 15 = 0

5^{2 x - 3} = 4