What are the solutions to the equation 12x^2-40x-63=0 ?

The solutions to the equation 12x^2-40x-63=0 are x= 9/2 ,x=-7/6

Find the zeros of 12x^2-40x-63=0

The zeros of 12x^2-40x-63=0 are x= 9/2 ,x=-7/6

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12 x^{2} - 40 x - 63 = 0

x = \frac{9}{2}, x = - \frac{7}{6}

Solution steps

12 x^{2} - 40 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 12 ( - 63 )}{2 \cdot 12}

(- 40)^{2} - 4 \cdot 12 (- 63) = 68

x_{1, 2} = \frac{- ( - 40 ) \pm 68}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 68}{2 \cdot 12}, x_{2} = \frac{- ( - 40 ) - 68}{2 \cdot 12}

x = \frac{- ( - 40 ) + 68}{2 \cdot 12} : \frac{9}{2}

x = \frac{- ( - 40 ) - 68}{2 \cdot 12} : - \frac{7}{6}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{7}{6}

3 x + 5 = 1

(\frac{3}{5})^{4}

120

(2 a - b) (2 x - 2 y)^{2} - (6 a - 3 b)^{3} (x - y)

(y^{\frac{1}{2}})^{2}

What are the solutions to the equation 12x^2-40x-63=0 ?
The solutions to the equation 12x^2-40x-63=0 are x= 9/2 ,x=-7/6
Find the zeros of 12x^2-40x-63=0
The zeros of 12x^2-40x-63=0 are x= 9/2 ,x=-7/6