What are the solutions to the equation 3x^2-11x+6=0 ?

The solutions to the equation 3x^2-11x+6=0 are x=3,x= 2/3

Find the zeros of 3x^2-11x+6=0

The zeros of 3x^2-11x+6=0 are x=3,x= 2/3

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3 x^{2} - 11 x + 6 = 0

x = 3, x = \frac{2}{3}

Solution steps

3 x^{2} - 11 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 \cdot 6 = 7

x_{1, 2} = \frac{- ( - 11 ) \pm 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 7}{2 \cdot 3}, x_{2} = \frac{- ( - 11 ) - 7}{2 \cdot 3}

x = \frac{- ( - 11 ) + 7}{2 \cdot 3} : 3

x = \frac{- ( - 11 ) - 7}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

x = 3, x = \frac{2}{3}

4 \cdot 2^{- 1}

(4 c - d) (c + 5 d) - 3 (d - 4 c)

(y^{3})^{3}

64 x^{2} - 100

5 x - 14 = 8 x + 4

What are the solutions to the equation 3x^2-11x+6=0 ?
The solutions to the equation 3x^2-11x+6=0 are x=3,x= 2/3
Find the zeros of 3x^2-11x+6=0
The zeros of 3x^2-11x+6=0 are x=3,x= 2/3