What is the answer to (x-2)/3-(x+3)/6 =(x+1)/(12) ?

The answer to (x-2)/3-(x+3)/6 =(x+1)/(12) is x=15

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(x-2)/3-(x+3)/6 =(x+1)/(12)

\frac{x - 2}{3} - \frac{x + 3}{6} = \frac{x + 1}{12}

x = 15

Solution steps

\frac{x - 2}{3} - \frac{x + 3}{6} = \frac{x + 1}{12}

Multiply by LCM

4 (x - 2) - 2 (x + 3) = x + 1

Expand

4 (x - 2) - 2 (x + 3) : 2 x - 14

2 x - 14 = x + 1

Move

14

to the right side

2 x = x + 15

Move

x

to the left side

x = 15

4 k - 6 < 3 k + k - 1

3 x^{2} + 2 x + 9 = 0

- 3 \leq x \leq 3

\frac{1}{2} (72)

4 r^{2} + 21 r + 5

What is the answer to (x-2)/3-(x+3)/6 =(x+1)/(12) ?
The answer to (x-2)/3-(x+3)/6 =(x+1)/(12) is x=15
Solve for x: (x-2)/3-(x+3)/6 =(x+1)/(12)
The solution is x=15