What is the answer to |x+1|=x^2-19 ?

The answer to |x+1|=x^2-19 is x=(-1-sqrt(73))/2 \lor x=5

Solve for x: |x+1|=x^2-19

The solution is x=(-1-sqrt(73))/2 \lor x=5

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∣ x + 1 ∣ = x^{2} - 19

x = \frac{- 1 - 73}{2} or x = 5

Solution steps

∣ x + 1 ∣ = x^{2} - 19

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

x = \frac{- 1 - 73}{2} or x = 5

7 ∣ x ∣ - 1 = 41

(\frac{3}{2})^{1}

\frac{3}{n - 4} + \frac{3}{5 n - 6}

∣ 4 x + 9 ∣ + 2 = 7

\frac{1}{5} (q + 3) = \frac{1}{2} (q - 3)

What is the answer to |x+1|=x^2-19 ?
The answer to |x+1|=x^2-19 is x=(-1-sqrt(73))/2 \lor x=5
Solve for x: |x+1|=x^2-19
The solution is x=(-1-sqrt(73))/2 \lor x=5