vereinfachen (27a^6b^{-3})^{2/3}

Lösung

vereinfachen

(27 a^{6} b^{- 3})^{\frac{2}{3}}

\frac{9 a ^{4}}{b ^{2}}

Schritte zur Lösung

(27 a^{6} b^{- 3})^{\frac{2}{3}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(27 a^{6} b^{- 3})^{\frac{2}{3}} = 2 7^{\frac{2}{3}} (a^{6})^{\frac{2}{3}} (b^{- 3})^{\frac{2}{3}}

= 2 7^{\frac{2}{3}} (a^{6})^{\frac{2}{3}} (b^{- 3})^{\frac{2}{3}}

2 7^{\frac{2}{3}} = 9

= 9 (a^{6})^{\frac{2}{3}} (b^{- 3})^{\frac{2}{3}}

Vereinfache

(a^{6})^{\frac{2}{3}} : a^{4}

= 9 a^{4} (b^{- 3})^{\frac{2}{3}}

Vereinfache

(b^{- 3})^{\frac{2}{3}} : \frac{1}{b ^{2}}

= 9 a^{4} \frac{1}{b ^{2}}

Vereinfache

9 a^{4} \frac{1}{b ^{2}} : \frac{9 a ^{4}}{b ^{2}}

= \frac{9 a ^{4}}{b ^{2}}

s im pl i f y \frac{c + \frac{125}{c ^{2}}}{1 + \frac{5}{c}}

p^{2} + 14 p - 3 = 0

s im pl i f y \frac{1}{4 - 3}

f a c t or 8 x^{3} + 72 x^{2} + 160 x

x + 9 = 5 x - 11