What are the solutions to the equation x^2+10x+21=0 ?

The solutions to the equation x^2+10x+21=0 are x=-3,x=-7

Find the zeros of x^2+10x+21=0

The zeros of x^2+10x+21=0 are x=-3,x=-7

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x^{2} + 10 x + 21 = 0

x = - 3, x = - 7

Solution steps

x^{2} + 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4}{2 \cdot 1}, x_{2} = \frac{- 10 - 4}{2 \cdot 1}

x = \frac{- 10 + 4}{2 \cdot 1} : - 3

x = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

\frac{x}{300} + \frac{x}{700} = 1

\frac{x}{12} \geq - 3

- \frac{4}{6}

6 (1 - x)^{2} - 4 (1 - x)^{3} - 6 x (1 - x)^{2} - 1

(16 rs)^{\frac{3}{4}}

What are the solutions to the equation x^2+10x+21=0 ?
The solutions to the equation x^2+10x+21=0 are x=-3,x=-7
Find the zeros of x^2+10x+21=0
The zeros of x^2+10x+21=0 are x=-3,x=-7