What are the solutions to the equation (m+3)^2=0 ?

The solutions to the equation (m+3)^2=0 are m=-3

Find the zeros of (m+3)^2=0

The zeros of (m+3)^2=0 are m=-3

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(m + 3)^{2} = 0

m = - 3

Solution steps

(m + 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

m + 3 = 0 : m = - 3

The solution to the quadratic equation is:

m = - 3

2 x - x^{2}

(7 x + 4)^{2} = 4

12 a \geq - 24

\frac{2 x - 7}{3} = 5 - \frac{3 x - 2}{4}

- \frac{1}{8} + \frac{5}{6} - \frac{5}{12}

What are the solutions to the equation (m+3)^2=0 ?
The solutions to the equation (m+3)^2=0 are m=-3
Find the zeros of (m+3)^2=0
The zeros of (m+3)^2=0 are m=-3