What are the solutions to the equation 10y^2+11y-6=0 ?

The solutions to the equation 10y^2+11y-6=0 are y= 2/5 ,y=-3/2

Find the zeros of 10y^2+11y-6=0

The zeros of 10y^2+11y-6=0 are y= 2/5 ,y=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 y^{2} + 11 y - 6 = 0

y = \frac{2}{5}, y = - \frac{3}{2}

Solution steps

10 y^{2} + 11 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 10 ( - 6 )}{2 \cdot 10}

1 1^{2} - 4 \cdot 10 (- 6) = 19

y_{1, 2} = \frac{- 11 \pm 19}{2 \cdot 10}

Separate the solutions

y_{1} = \frac{- 11 + 19}{2 \cdot 10}, y_{2} = \frac{- 11 - 19}{2 \cdot 10}

y = \frac{- 11 + 19}{2 \cdot 10} : \frac{2}{5}

y = \frac{- 11 - 19}{2 \cdot 10} : - \frac{3}{2}

The solutions to the quadratic equation are:

y = \frac{2}{5}, y = - \frac{3}{2}

10 x^{2} = 6 + 9 x

5 - 5

∣ 3 x + 1 ∣ = 5

(x - 3) (x + 4) < 0

x^{2} - 13 x + 30 = 0

What are the solutions to the equation 10y^2+11y-6=0 ?
The solutions to the equation 10y^2+11y-6=0 are y= 2/5 ,y=-3/2
Find the zeros of 10y^2+11y-6=0
The zeros of 10y^2+11y-6=0 are y= 2/5 ,y=-3/2