What are the solutions to the equation x^2+8x+22=0 ?

The solutions to the equation x^2+8x+22=0 are x=-4+sqrt(6)i,x=-4-sqrt(6)i

Find the zeros of x^2+8x+22=0

The zeros of x^2+8x+22=0 are x=-4+sqrt(6)i,x=-4-sqrt(6)i

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x^{2} + 8 x + 22 = 0

x = - 4 + 6 i, x = - 4 - 6 i

Solution steps

x^{2} + 8 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 22 : 26 i

x_{1, 2} = \frac{- 8 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 6 i}{2 \cdot 1}

x = \frac{- 8 + 2 6 i}{2 \cdot 1} : - 4 + 6 i

x = \frac{- 8 - 2 6 i}{2 \cdot 1} : - 4 - 6 i

The solutions to the quadratic equation are:

x = - 4 + 6 i, x = - 4 - 6 i

x^{5} + x y^{3}

- 4 (- c - 24) = - 4 c - 24

∣ 5 a + 9 ∣ = ∣ 6 a - 3 ∣

5 x^{2} - x + 1 = 0

3 v^{2} - 6 v + 2 = 3

What are the solutions to the equation x^2+8x+22=0 ?
The solutions to the equation x^2+8x+22=0 are x=-4+sqrt(6)i,x=-4-sqrt(6)i
Find the zeros of x^2+8x+22=0
The zeros of x^2+8x+22=0 are x=-4+sqrt(6)i,x=-4-sqrt(6)i