What are the solutions to the equation x^2-10=-3x ?

The solutions to the equation x^2-10=-3x are x=2,x=-5

Find the zeros of x^2-10=-3x

The zeros of x^2-10=-3x are x=2,x=-5

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x^{2} - 10 = - 3 x

x = 2, x = - 5

Solution steps

x^{2} - 10 = - 3 x

Move

3 x

to the left side

x^{2} - 10 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

(x - 5)^{2} (x + 1) < 0

x^{2} - 6 x - 72

(- 1 - 3 i) \cdot (- 1 + i)

6^{- \frac{5}{4}} \cdot 6^{- \frac{8}{7}}

14 \cdot 1012

What are the solutions to the equation x^2-10=-3x ?
The solutions to the equation x^2-10=-3x are x=2,x=-5
Find the zeros of x^2-10=-3x
The zeros of x^2-10=-3x are x=2,x=-5