What are the solutions to the equation 2a^2+5a-5=0 ?

The solutions to the equation 2a^2+5a-5=0 are a=(-5+sqrt(65))/4 ,a=(-5-sqrt(65))/4

Find the zeros of 2a^2+5a-5=0

The zeros of 2a^2+5a-5=0 are a=(-5+sqrt(65))/4 ,a=(-5-sqrt(65))/4

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2 a^{2} + 5 a - 5 = 0

a = \frac{- 5 + 65}{4}, a = \frac{- 5 - 65}{4}

Solution steps

2 a^{2} + 5 a - 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 5) = 65

a_{1, 2} = \frac{- 5 \pm 65}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 5 + 65}{2 \cdot 2}, a_{2} = \frac{- 5 - 65}{2 \cdot 2}

a = \frac{- 5 + 65}{2 \cdot 2} : \frac{- 5 + 65}{4}

a = \frac{- 5 - 65}{2 \cdot 2} : \frac{- 5 - 65}{4}

The solutions to the quadratic equation are:

a = \frac{- 5 + 65}{4}, a = \frac{- 5 - 65}{4}

0.0014 > 0.000012

2 - x = - 3 + x

\frac{4}{x - 1} \geq 0

9 x^{2} - 100

\frac{16}{81}

What are the solutions to the equation 2a^2+5a-5=0 ?
The solutions to the equation 2a^2+5a-5=0 are a=(-5+sqrt(65))/4 ,a=(-5-sqrt(65))/4
Find the zeros of 2a^2+5a-5=0
The zeros of 2a^2+5a-5=0 are a=(-5+sqrt(65))/4 ,a=(-5-sqrt(65))/4