What is the answer to (2x+1)^2-(2x-1)^2=(x+6)^2-x^2 ?

The answer to (2x+1)^2-(2x-1)^2=(x+6)^2-x^2 is x=-9

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(2x+1)^2-(2x-1)^2=(x+6)^2-x^2

(2 x + 1)^{2} - (2 x - 1)^{2} = (x + 6)^{2} - x^{2}

x = - 9

Solution steps

(2 x + 1)^{2} - (2 x - 1)^{2} = (x + 6)^{2} - x^{2}

Expand

(2 x + 1)^{2} - (2 x - 1)^{2} : 8 x

Expand

(x + 6)^{2} - x^{2} : 12 x + 36

8 x = 12 x + 36

Move

12 x

to the left side

- 4 x = 36

Divide both sides by

- 4

x = - 9

(3 x^{3})^{2}

(\frac{1}{6})^{- 2}

7 + 5 (x - 3) = 22

x^{2} + 18 x + 54 = 4 x + 9

- 57 = - (- p + 1) + 2 (6 + 8 p)

What is the answer to (2x+1)^2-(2x-1)^2=(x+6)^2-x^2 ?
The answer to (2x+1)^2-(2x-1)^2=(x+6)^2-x^2 is x=-9
Solve for x: (2x+1)^2-(2x-1)^2=(x+6)^2-x^2
The solution is x=-9