What are the solutions to the equation 49x^2-70x+25=64 ?

The solutions to the equation 49x^2-70x+25=64 are x= 13/7 ,x=-3/7

Find the zeros of 49x^2-70x+25=64

The zeros of 49x^2-70x+25=64 are x= 13/7 ,x=-3/7

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49 x^{2} - 70 x + 25 = 64

x = \frac{13}{7}, x = - \frac{3}{7}

Solution steps

49 x^{2} - 70 x + 25 = 64

Move

64

to the left side

49 x^{2} - 70 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 49 ( - 39 )}{2 \cdot 49}

(- 70)^{2} - 4 \cdot 49 (- 39) = 112

x_{1, 2} = \frac{- ( - 70 ) \pm 112}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 70 ) + 112}{2 \cdot 49}, x_{2} = \frac{- ( - 70 ) - 112}{2 \cdot 49}

x = \frac{- ( - 70 ) + 112}{2 \cdot 49} : \frac{13}{7}

x = \frac{- ( - 70 ) - 112}{2 \cdot 49} : - \frac{3}{7}

The solutions to the quadratic equation are:

x = \frac{13}{7}, x = - \frac{3}{7}

x^{3} - 7 x^{2} + 14 x - 8

w^{2} - 16 w + 64

\frac{w}{2} + 8 < 9

3 + 1

\frac{3 x + 6}{2} < 3

What are the solutions to the equation 49x^2-70x+25=64 ?
The solutions to the equation 49x^2-70x+25=64 are x= 13/7 ,x=-3/7
Find the zeros of 49x^2-70x+25=64
The zeros of 49x^2-70x+25=64 are x= 13/7 ,x=-3/7