What are the solutions to the equation 2x^4-7x^3+12x^2-8x-8=0 ?

The solutions to the equation 2x^4-7x^3+12x^2-8x-8=0 are x=2,x=-1/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of 2x^4-7x^3+12x^2-8x-8=0

The zeros of 2x^4-7x^3+12x^2-8x-8=0 are x=2,x=-1/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i

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2 x^{4} - 7 x^{3} + 12 x^{2} - 8 x - 8 = 0

x = 2, x = - \frac{1}{2}, x = 1 + 3 i, x = 1 - 3 i

Solution steps

2 x^{4} - 7 x^{3} + 12 x^{2} - 8 x - 8 = 0

Factor

2 x^{4} - 7 x^{3} + 12 x^{2} - 8 x - 8 : (x - 2) (2 x + 1) (x^{2} - 2 x + 4)

(x - 2) (2 x + 1) (x^{2} - 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 1 = 0 or x^{2} - 2 x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x^{2} - 2 x + 4 = 0 : x = 1 + 3 i, x = 1 - 3 i

The solutions are

x = 2, x = - \frac{1}{2}, x = 1 + 3 i, x = 1 - 3 i

6 (- y + 4) - 3 (2 y - 3) = - y + 5 + 5 y

3 m^{2} + 6 m + 3

x^{3} (x^{2})

9 w^{2} - 64

2 x - 8 < 12

What are the solutions to the equation 2x^4-7x^3+12x^2-8x-8=0 ?
The solutions to the equation 2x^4-7x^3+12x^2-8x-8=0 are x=2,x=-1/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of 2x^4-7x^3+12x^2-8x-8=0
The zeros of 2x^4-7x^3+12x^2-8x-8=0 are x=2,x=-1/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i