erweitern ([a+7(b-3)]^2)/3

Lösung

erweitern

\frac{[ a + 7 ( b - 3 ) ] ^{2}}{3}

\frac{14 ab}{3} + \frac{a ^{2}}{3} - 14 a + \frac{49 b ^{2}}{3} - 98 b + 147

Schritte zur Lösung

\frac{( a + 7 ( b - 3 ) ) ^{2}}{3}

(a + 7 (b - 3))^{2} = 14 ab + a^{2} - 42 a + 49 b^{2} - 294 b + 441

= \frac{14 ab + a ^{2} - 42 a + 49 b ^{2} - 294 b + 441}{3}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{14 ab + a ^{2} - 42 a + 49 b ^{2} - 294 b + 441}{3} = \frac{14 ab}{3} + \frac{a ^{2}}{3} - \frac{42 a}{3} + \frac{49 b ^{2}}{3} - \frac{294 b}{3} + \frac{441}{3}

= \frac{14 ab}{3} + \frac{a ^{2}}{3} - \frac{42 a}{3} + \frac{49 b ^{2}}{3} - \frac{294 b}{3} + \frac{441}{3}

Teile die Zahlen:

\frac{42}{3} = 14

= \frac{14 ab}{3} + \frac{a ^{2}}{3} - 14 a + \frac{49 b ^{2}}{3} - \frac{294 b}{3} + \frac{441}{3}

Teile die Zahlen:

\frac{294}{3} = 98

= \frac{14 ab}{3} + \frac{a ^{2}}{3} - 14 a + \frac{49 b ^{2}}{3} - 98 b + \frac{441}{3}

Teile die Zahlen:

\frac{441}{3} = 147

= \frac{14 ab}{3} + \frac{a ^{2}}{3} - 14 a + \frac{49 b ^{2}}{3} - 98 b + 147

e x p an d \frac{( z - y ) ^{2}}{x}

e x p an d 2 H (t - 2) (t - 2) - t + 4 H (t)

e x p an d \frac{10 ( s + 1 )}{s ^{2} + s + 10}

e x p an d \frac{4 x + 5}{( x - 2 ) ^{3} ( x + 3 )}

e x p an d \frac{3 a ( a - 2 b ) ^{2}}{2 b ^{3}}