What is (20n^3+15n^2)/(20n^2+10n) ?

The solution to (20n^3+15n^2)/(20n^2+10n) is (n(4n+3))/(2(2n+1))

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simplify (20n^3+15n^2)/(20n^2+10n)

simplify

\frac{20 n ^{3} + 15 n ^{2}}{20 n ^{2} + 10 n}

\frac{n ( 4 n + 3 )}{2 ( 2 n + 1 )}

Solution steps

\frac{20 n ^{3} + 15 n ^{2}}{20 n ^{2} + 10 n}

Factor

20 n^{3} + 15 n^{2} : 5 n^{2} (4 n + 3)

= \frac{5 n ^{2} ( 4 n + 3 )}{20 n ^{2} + 10 n}

Factor

20 n^{2} + 10 n : 10 n (2 n + 1)

= \frac{5 n ^{2} ( 4 n + 3 )}{10 n ( 2 n + 1 )}

Factor the number:

10 = 5 \cdot 2

= \frac{5 n ^{2} ( 4 n + 3 )}{5 \cdot 2 n ( 2 n + 1 )}

Cancel the common factor:

5

= \frac{n ^{2} ( 4 n + 3 )}{2 n ( 2 n + 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

n^{2} = nn

= \frac{nn ( 4 n + 3 )}{2 n ( 2 n + 1 )}

Cancel the common factor:

n

= \frac{n ( 4 n + 3 )}{2 ( 2 n + 1 )}

x^{2} = 81

x^{2} + 7 x + 1 = 0

\frac{1}{1 + i} - \frac{1}{1 - i}

w^{4} - 14 w^{2} - 32

- 9 + \frac{a}{- 10} = - 8

What is (20n^3+15n^2)/(20n^2+10n) ?
The solution to (20n^3+15n^2)/(20n^2+10n) is (n(4n+3))/(2(2n+1))