What are the solutions to the equation 4(x-5)^2-2=26 ?

The solutions to the equation 4(x-5)^2-2=26 are x=sqrt(7)+5,x=-sqrt(7)+5

Find the zeros of 4(x-5)^2-2=26

The zeros of 4(x-5)^2-2=26 are x=sqrt(7)+5,x=-sqrt(7)+5

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4 (x - 5)^{2} - 2 = 26

x = 7 + 5, x = - 7 + 5

Solution steps

4 (x - 5)^{2} - 2 = 26

Move

2

to the right side

4 (x - 5)^{2} = 28

Divide both sides by

4

(x - 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 7 : x = 7 + 5

Solve

x - 5 = - 7 : x = - 7 + 5

The solutions to the quadratic equation are:

x = 7 + 5, x = - 7 + 5

(x^{\frac{2}{3}})^{3}

8 q^{2} - 10 q + 3 = 0

\frac{7}{13} h + 89 = 110

x^{5} \cdot x^{5}

- x^{2} + 4 x - 4 = 0

What are the solutions to the equation 4(x-5)^2-2=26 ?
The solutions to the equation 4(x-5)^2-2=26 are x=sqrt(7)+5,x=-sqrt(7)+5
Find the zeros of 4(x-5)^2-2=26
The zeros of 4(x-5)^2-2=26 are x=sqrt(7)+5,x=-sqrt(7)+5