What is the answer to |y-1|=1-y ?

The answer to |y-1|=1-y is y<= 1

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|y-1|=1-y

∣ y - 1 ∣ = 1 - y

y \leq 1

Solution steps

∣ y - 1 ∣ = 1 - y

Find positive and negative intervals

y < 1, y \geq 1

Solve the inequality for each interval

y < 1 or y = 1

Merge Overlapping Intervals

y \leq 1

8 x^{2} = 4 x

\frac{π}{2} - \frac{π}{5}

3 x + 15 - 9 = 2 (x + 2)

\frac{3 x - 1}{5} - \frac{x - 2}{2} = x + 4

\frac{3 x}{4} = 9