What are the solutions to the equation 2x^2-6x+8=0 ?

The solutions to the equation 2x^2-6x+8=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

Find the zeros of 2x^2-6x+8=0

The zeros of 2x^2-6x+8=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2

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2 x^{2} - 6 x + 8 = 0

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

Solution steps

2 x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 8 : 27 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 7 i}{2 \cdot 2} : \frac{3}{2} + i \frac{7}{2}

x = \frac{- ( - 6 ) - 2 7 i}{2 \cdot 2} : \frac{3}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{7}{2}, x = \frac{3}{2} - i \frac{7}{2}

\frac{( x - 8 )}{25} + \frac{( x - 17 )}{140} + \frac{x}{10} = 0

e^{2 \cdot l n (2)}

2 (x + 3) = 1

(x - 2) (x - 3) = 0

- ∣ x + 2 ∣ + 9 = - 5

What are the solutions to the equation 2x^2-6x+8=0 ?
The solutions to the equation 2x^2-6x+8=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2
Find the zeros of 2x^2-6x+8=0
The zeros of 2x^2-6x+8=0 are x= 3/2+i(sqrt(7))/2 ,x= 3/2-i(sqrt(7))/2