What are the solutions to the equation (x-1)(x+4)=36 ?

The solutions to the equation (x-1)(x+4)=36 are x=5,x=-8

Find the zeros of (x-1)(x+4)=36

The zeros of (x-1)(x+4)=36 are x=5,x=-8

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(x - 1) (x + 4) = 36

x = 5, x = - 8

Solution steps

(x - 1) (x + 4) = 36

Expand

(x - 1) (x + 4) : x^{2} + 3 x - 4

x^{2} + 3 x - 4 = 36

Move

36

to the left side

x^{2} + 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 13}{2 \cdot 1}, x_{2} = \frac{- 3 - 13}{2 \cdot 1}

x = \frac{- 3 + 13}{2 \cdot 1} : 5

x = \frac{- 3 - 13}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 5, x = - 8

205 < - 5 (7 v - 6)

2 x^{3} - 6 x^{2} - a x + 3 a

(2 x - 3) (3 x - 2) < 0

\frac{5}{7} \cdot \frac{5}{8}

∣ x ∣ > 2 x - 1

What are the solutions to the equation (x-1)(x+4)=36 ?
The solutions to the equation (x-1)(x+4)=36 are x=5,x=-8
Find the zeros of (x-1)(x+4)=36
The zeros of (x-1)(x+4)=36 are x=5,x=-8